Galactic Cartography

In your last podcast, you have talked about mapping a galaxy and that made me think about, how I would do it. I am interested, what
you think of it...

So here is, what I thought of:
First we going to need a central point and the three axis. 
These things are of course arbitrary, but because each galaxy has a central point and one side, where it is thinnest.
At least the centre point and the x-Axis is well defined. Now we create a sphere with a radius of one unit length around the centre.
This will be the basis for the rest of the mapping. We cut this sphere into 8 equal pieces along the planes, created by the axis.
We get 8 pieces, that have a area of pi/6 volume units. The idea is, that we divide the entire universe into blocks with the same
volume. So next we create a slightly bigger sphere, subtract the original sphere and divide it again in 8 pieces. Since these pieces will
be bigger than the original pieces, because volume grows faster, than the radius, we divide each block into 4 pieces. These new pieces will
be as big, as the original 8 pieces and have the volume of pi/6 volume units. And that way we continue: Always making a bigger sphere and
dividing it up into more parts.
The radius of the sphere at iteration x will be r(x)=((4^(x+1)-1)/3)^(1/3) and the numbers of pieces will be E(x)=8*4^x.
If we look at the spherical shell we get a volume of 4/3*pi*(r(x)^3-r(x-1)^3) and one piece will have a volume of
4/(3*E(x))*pi*(r(x)^3-r(x-1)^3) = 4/(3*E(x))*pi*(4^(x)*3)/3) = (12*4^x*pi)/(9*8*4^x) = pi/6 so we can see, that it works.

You might ask:
Why would we want to do this?

There are a couple of advantages:

1. If the volume is constant, there each piece will contain about the same number of object (assuming the Objects are distributed equally).
It also means, that the pieces stay at a manageable size.
2. Each of the pieces can be identified by a number in base 4 and the information whether you are above or below the y/z plane.
You start at the centre:
You can decode it quite easily:
a: We are above the y/z plane.
Now we start at the centre and pick the part with the number of the next digit. (It will always be 1 of 4 parts, that is why the name is in base 4),

This also means, that the distance to the centre of the galaxy can be directly encoded into the naming (r(log4(name))).
I might have let my inner computer scientist a bit loose with all the addressing.
But what do you think? I'm quite interested about your opinion.